x^2+(2m+1)-5=0

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Solution for x^2+(2m+1)-5=0 equation:


Simplifying
x2 + (2m + 1) + -5 = 0

Reorder the terms:
x2 + (1 + 2m) + -5 = 0

Remove parenthesis around (1 + 2m)
x2 + 1 + 2m + -5 = 0

Reorder the terms:
1 + -5 + 2m + x2 = 0

Combine like terms: 1 + -5 = -4
-4 + 2m + x2 = 0

Solving
-4 + 2m + x2 = 0

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 2m + 4 + x2 = 0 + 4

Reorder the terms:
-4 + 4 + 2m + x2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 2m + x2 = 0 + 4
2m + x2 = 0 + 4

Combine like terms: 0 + 4 = 4
2m + x2 = 4

Add '-1x2' to each side of the equation.
2m + x2 + -1x2 = 4 + -1x2

Combine like terms: x2 + -1x2 = 0
2m + 0 = 4 + -1x2
2m = 4 + -1x2

Divide each side by '2'.
m = 2 + -0.5x2

Simplifying
m = 2 + -0.5x2

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